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Electromagnetic Waves in Matter

Electromagnetic waves propagate through matter as well as vacuum, but with a modified speed $v=c/n$ where $n=\sqrt{\varepsilon_r\mu_r}$ is the index of refraction. At boundaries between media, waves are partially reflected and partially transmitted according to the Fresnel equations. Dispersion — the frequency-dependence of $n$ — is the origin of rainbows.

Key Concepts

Wave in Medium
Speed v=c/nv=c/n, wavelength λ=λ0/n\lambda=\lambda_0/n, frequency unchanged. Amplitude decays in lossy media as eαz/2e^{-\alpha z/2} where α\alpha is the absorption coefficient.
Index of Refraction
n=εrμrεrn=\sqrt{\varepsilon_r\mu_r}\approx\sqrt{\varepsilon_r} (for non-magnetic media). Depends on frequency (dispersion). Snell's law: n1sinθ1=n2sinθ2n_1\sin\theta_1=n_2\sin\theta_2.
Fresnel Equations
Reflection and transmission amplitudes at normal incidence: r=(n1n2)/(n1+n2)r=(n_1-n_2)/(n_1+n_2), t=2n1/(n1+n2)t=2n_1/(n_1+n_2). Reflectance: R=r2=[(n1n2)/(n1+n2)]2R=r^2=[(n_1-n_2)/(n_1+n_2)]^2.
Total Internal Reflection
When n1>n2n_1>n_2, light can't escape if θ1>θc=arcsin(n2/n1)\theta_1>\theta_c=\arcsin(n_2/n_1). This is the basis of optical fibers.

Key Equations

Wave speed in medium
v=cn=1μεv = \frac{c}{n} = \frac{1}{\sqrt{\mu\varepsilon}}
Speed of EM wave in medium with permittivity ε and permeability μ.
Fresnel (normal incidence)
R=(n1n2n1+n2)2,T=1RR = \left(\frac{n_1-n_2}{n_1+n_2}\right)^2, \quad T = 1-R
Reflectance R and transmittance T at a planar interface.
Critical angle
θc=arcsin(n2n1)\theta_c = \arcsin\left(\frac{n_2}{n_1}\right)
Angle of total internal reflection; exists only when n₁ > n₂.
Worked Example

Reflection at Glass-Air Interface

Problem

Light travels from glass (n1=1.5n_1=1.5) to air (n2=1.0n_2=1.0) at normal incidence. Find the reflectance RR and the critical angle θc\theta_c.

Solution
R=(1.51.01.5+1.0)2=(0.52.5)2=(0.20)2=0.04=4%R = \left(\frac{1.5-1.0}{1.5+1.0}\right)^2 = \left(\frac{0.5}{2.5}\right)^2 = (0.20)^2 = 0.04 = 4\%
θc=arcsin(n2/n1)=arcsin(1.0/1.5)=arcsin(0.667)=41.8°\theta_c = \arcsin(n_2/n_1) = \arcsin(1.0/1.5) = \arcsin(0.667) = 41.8°
Answer R=4%R=4\%; θc=41.8°\theta_c=41.8°.
Practice

Exercises

7 problems
1 of 7

Light travels through glass (n=1.50n=1.50). Find its speed (in m/s).

m/s
2 of 7

Find the reflectance RR at normal incidence for air (n1=1.0n_1=1.0) to glass (n2=1.5n_2=1.5). R=((n1n2)/(n1+n2))2R=((n_1-n_2)/(n_1+n_2))^2.

(dimensionless)
3 of 7

Critical angle for total internal reflection from glass (n1=1.5n_1=1.5) to air (n2=1.0n_2=1.0). θc=arcsin(n2/n1)\theta_c=\arcsin(n_2/n_1) (in degrees).

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4 of 7

A light wave in vacuum has λ0=600\lambda_0=600 nm. In glass (n=1.5n=1.5), find λ\lambda (in nm).

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5 of 7

Snell's law: light goes from water (n1=1.33n_1=1.33) to glass (n2=1.50n_2=1.50) at θ1=30°\theta_1=30°. Find θ2\theta_2 (in degrees). sinθ2=n1sinθ1/n2\sin\theta_2=n_1\sin\theta_1/n_2.

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6 of 7

Brewster's angle for air-glass (n1=1.0,n2=1.5n_1=1.0,n_2=1.5): tanθB=n2/n1=1.5\tan\theta_B=n_2/n_1=1.5. Find θB\theta_B (in degrees).

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7 of 7

An optical fiber has core n1=1.50n_1=1.50 and cladding n2=1.45n_2=1.45. Find the numerical aperture NA=n12n22NA=\sqrt{n_1^2-n_2^2}.

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Key Takeaways

  • EM waves travel at v=c/nv=c/n in a medium; frequency is unchanged, wavelength is λ0/n\lambda_0/n.
  • Fresnel equations give reflection and transmission at interfaces; R+T=1R+T=1 (for energy).
  • Total internal reflection occurs when θ1>θc=arcsin(n2/n1)\theta_1>\theta_c=\arcsin(n_2/n_1) with n1>n2n_1>n_2.
  • Brewster's angle: at tanθB=n2/n1\tan\theta_B=n_2/n_1, reflected light is perfectly ss-polarized.