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Diffraction

Diffraction occurs when waves bend around obstacles or through openings. Single-slit diffraction produces a central bright maximum flanked by weaker side bands. Diffraction gratings are precise tools for spectroscopy.

Key Concepts

  • Single-slit first minimum: a sinθ = λ
  • Grating: d sinθ = mλ for principal maxima
  • Resolving power: R = λ/Δλ = mN
  • Rayleigh criterion: θ_min = 1.22λ/D
  • X-ray diffraction: 2d sinθ = mλ (Bragg)

Key Equations

Single-slit dark fringe
asinθ=mλ,m=±1,±2,a\sin\theta = m\lambda,\quad m=\pm1,\pm2,\ldots
Grating equation
dsinθ=mλd\sin\theta = m\lambda
Resolving power
R=mN=λΔλR = mN = \frac{\lambda}{\Delta\lambda}
Rayleigh criterion
θmin=1.22λD\theta_{\min} = 1.22\frac{\lambda}{D}
Worked Example

Example Problem

Problem

A diffraction grating has 500 lines/mm and is illuminated by λ=550 nm. Find the angle of the 1st-order maximum.

Solution

d = 1/500 mm = 2×10⁻⁶ m. sinθ = mλ/d = 550×10⁻⁹/2×10⁻⁶ = 0.275. θ = 15.96°.

Practice

Exercises

7 problems
1 of 7

A 600 lines/mm grating is illuminated by λ=500 nm. Find the angle of the m=1 maximum in degrees.

degrees
2 of 7

A single slit of width a=0.2 mm is illuminated by λ=600 nm. Find the angular width of the central maximum (2θ₁) in degrees.

degrees
3 of 7

A grating has 1200 lines/mm, width 1 cm, illuminated by λ=550 nm. Find the resolving power R in 1st order.

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4 of 7

A telescope has objective diameter D=10 cm. Find the minimum angular resolution (Rayleigh criterion) for λ=550 nm in arcseconds.

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5 of 7

X-rays (λ=0.154 nm) diffract from crystal planes (d=0.314 nm). Find the Bragg angle for m=1 in degrees.

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6 of 7

A diffraction grating resolves two sodium lines at λ=589.0 nm and λ=589.6 nm in 2nd order. How many lines must the grating have?

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7 of 7

In single-slit diffraction (a=1.0 mm, λ=600 nm, L=2.0 m), find the width of the central maximum on the screen in mm.

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Key Takeaways

  • Single-slit diffraction produces a broad central maximum with angular width 2λ/a
  • Diffraction gratings concentrate light into sharp maxima via constructive interference of many slits
  • Resolving power R = mN limits the ability to distinguish nearby wavelengths
  • The Rayleigh criterion gives the minimum angular separation two point sources can be resolved