← General Physics I
📐

Units & Measurement

Physics is a quantitative science — every result requires both a number and a unit. The International System of Units (SI) provides a universal framework so scientists worldwide can communicate unambiguously. Mastering dimensional analysis and significant figures is the foundation of all physics problem-solving.

1.1 The Role of Measurement in Physics

Physics is a quantitative science — every result is a number paired with a unit. Saying a distance is "12" is meaningless without specifying whether you mean meters, feet, or light-years. A force of "500" could describe the tension in a guitar string or the thrust of a rocket engine, depending on the unit. Units are not optional notation — they are part of the physical quantity itself.

This fact is more powerful than it first appears. Because units are algebraic objects that cancel and combine like variables, you can use them to check any equation you write and to derive relationships between physical quantities without solving a single equation. This technique is called dimensional analysis, and it is one of the most immediately useful skills in all of physics.

Every physically meaningful equation must be dimensionally consistent: every term on both sides must have the same dimensions. An equation that fails this check is guaranteed to be wrong — no exceptions.

The precision of a measurement matters equally. A result of 9.8 m/s29.8\text{ m/s}^2 and 9.80000 m/s29.80000\text{ m/s}^2 are the same number to two significant figures, but the second form claims six-figure precision. Reporting the right number of significant figures communicates how much confidence to place in each digit.

1.2 The International System of Units (SI)

In 1960, the General Conference on Weights and Measures (CGPM) established the Système International d'Unités — the International System of Units, abbreviated SI worldwide. It defines seven base quantities, each assigned a single standard unit. Every other physical unit in existence is derived from these seven through multiplication and division.

The Seven SI Base Units
QuantityUnit nameSymbolDimension
Lengthmeterm[L][L]
Masskilogramkg[M][M]
Timeseconds[T][T]
Electric currentampereA[I][I]
TemperaturekelvinK[Θ][\Theta]
Amount of substancemolemol[N][N]
Luminous intensitycandelacd[J][J]

Derived units are built from products and ratios of base units. For example, from Newton's second law F=maF = ma, force has units of mass × acceleration, so 1 newton=1 N=1 kgm/s21\text{ newton} = 1\text{ N} = 1\text{ kg}\cdot\text{m/s}^2. Similarly, 1 joule=1 J=1 Nm=1 kgm2/s21\text{ joule} = 1\text{ J} = 1\text{ N}\cdot\text{m} = 1\text{ kg}\cdot\text{m}^2\text{/s}^2, and 1 watt=1 W=1 J/s=1 kgm2/s31\text{ watt} = 1\text{ W} = 1\text{ J/s} = 1\text{ kg}\cdot\text{m}^2\text{/s}^3.

How the Base Units Are Defined

Since 2019, all seven SI base units are defined by fixing exact numerical values of fundamental constants of nature. The units are no longer tied to physical objects and can in principle be reproduced in any laboratory anywhere.

• The meter is defined by fixing the speed of light to exactly c=299,792,458 m/sc = 299{,}792{,}458\text{ m/s}. One meter is the distance light travels in 1/299,792,4581/299{,}792{,}458 of a second.

• The second is defined by the cesium-133 hyperfine transition: one second equals exactly 9,192,631,7709{,}192{,}631{,}770 oscillations of the microwave radiation emitted by a cesium-133 atom. Atomic clocks realize this to better than 1 part in 101610^{16}.

• The kilogram is defined by fixing Planck's constant to exactly h=6.62607015×1034 kgm2/sh = 6.62607015 \times 10^{-34}\text{ kg}\cdot\text{m}^2\text{/s}. This replaced the old platinum–iridium cylinder kept in a vault near Paris, which had been the world's mass standard since 1889.

1.3 SI Prefixes

Physical quantities span an enormous range — from the diameter of a proton (1015\sim 10^{-15} m) to the observable universe (1026\sim 10^{26} m), a ratio of 104110^{41}. The metric system handles this through prefixes that scale any SI unit by an exact power of ten.

Common SI Prefixes
PrefixSymbolFactorExample in physics
teraT101210^{12}global electric power: 18\sim 18 TW
gigaG10910^{9}CPU clock: 3 GHz
megaM10610^{6}radio: 100 MHz FM
kilok10310^{3}kilometer, kilowatt
(base)10010^{0}m, kg, s, A, K ...
centic10210^{-2}centimeter (cm)
millim10310^{-3}millisecond (ms)
microμ10610^{-6}micron = 10610^{-6} m; visible light 0.5μ\sim 0.5\,\mum
nanon10910^{-9}DNA strand: 2\sim 2 nm wide
picop101210^{-12}picosecond laser pulses
femtof101510^{-15}proton radius: 0.85\sim 0.85 fm
Commit these to memory: nano (10910^{-9}), micro (10610^{-6}), milli (10310^{-3}), kilo (10310^3), mega (10610^6), giga (10910^9). These appear constantly across physics, chemistry, engineering, and everyday technology.

Watch out for the kilogram: it is the SI base unit of mass, yet it already contains the "kilo" prefix. When attaching other prefixes to mass, you attach them to gram, not kilogram. So 1 milligram = 103 g=106 kg10^{-3}\text{ g} = 10^{-6}\text{ kg}.

1.4 Unit Conversion: The Chain-Link Method

Every unit conversion is multiplication by 1. If 1 km=1000 m1\text{ km} = 1000\text{ m}, then the ratio 1000 m1 km\frac{1000\text{ m}}{1\text{ km}} equals exactly 1 — multiplying any quantity by it changes nothing physically, only the units in which we express the result. Chain-link conversion strings together as many such identity fractions as needed.

The golden rule: write the units explicitly in every fraction, verify that unwanted units cancel before touching the arithmetic, and only compute after the algebra is clean.

Example — Converting speed

Convert 60 miles per hour to meters per second. (1 mi=1609 m1\text{ mi} = 1609\text{ m}, 1 hr=3600 s1\text{ hr} = 3600\text{ s}):

60mihr×1609m1mi×1hr3600s=60×16093600ms26.8m/s60\,\frac{\text{mi}}{\text{hr}} \times \frac{1609\,\text{m}}{1\,\text{mi}} \times \frac{1\,\text{hr}}{3600\,\text{s}} = \frac{60 \times 1609}{3600}\,\frac{\text{m}}{\text{s}} \approx 26.8\,\text{m/s}

The "mi" and "hr" each cancel between numerator and denominator, leaving only m/s. A useful shortcut: to convert any speed from km/h to m/s, divide by 3.6, because 1000/3600=1/3.61000/3600 = 1/3.6.

Example — Converting area and volume

A common error is forgetting to raise conversion factors to the appropriate power. To convert 1 cm21\text{ cm}^2 to m2\text{m}^2:

1cm2×(1m100cm) ⁣2=1104m2=104m21\,\text{cm}^2 \times \left(\frac{1\,\text{m}}{100\,\text{cm}}\right)^{\!2} = \frac{1}{10^4}\,\text{m}^2 = 10^{-4}\,\text{m}^2
Key rule for areas and volumes: cube the linear conversion factor when converting volume, square it when converting area. Never just divide by 100 when going from cm² to m² — you must divide by 1002=10,000100^2 = 10{,}000.

1.5 Dimensional Analysis

Every physical quantity has a dimension — an expression in terms of the fundamental types: length [L][L], mass [M][M], time [T][T], electric current [I][I], temperature [Θ][\Theta], amount [N][N], and luminous intensity [J][J]. Dimensions are more fundamental than units: velocity has dimension [LT1][LT^{-1}] whether you measure it in m/s, km/h, or furlongs per fortnight.

Dimensions of Common Physical Quantities
QuantityDimensionSI unit
Velocity vv[LT1][LT^{-1}]m/s
Acceleration aa[LT2][LT^{-2}]m/s²
Force FF[MLT2][MLT^{-2}]N = kg·m/s²
Energy EE[ML2T2][ML^2T^{-2}]J = kg·m²/s²
Power PP[ML2T3][ML^2T^{-3}]W = J/s
Pressure pp[ML1T2][ML^{-1}T^{-2}]Pa = N/m²
Momentum pp[MLT1][MLT^{-1}]kg·m/s
Frequency ff[T1][T^{-1}]Hz = s⁻¹

Checking Equations

A valid physical equation must be dimensionally consistent — every term on both sides must carry identical dimensions. This rule can immediately expose errors. Consider the kinematic equation x=x0+v0t+12at2x = x_0 + v_0 t + \frac{1}{2}at^2. Checking term by term:

[x0]=L,[v0t]=LTT=L,[12at2]=LT2T2=L[x_0] = L,\quad [v_0 t] = \frac{L}{T}\cdot T = L,\quad \left[\tfrac{1}{2}at^2\right] = \frac{L}{T^2}\cdot T^2 = L\quad\checkmark

All three terms have dimension [L][L]. If any term had, say, dimension [L2][L^2], the equation would be provably wrong — no further analysis needed.

Deriving Formulas from Dimensions

Suppose you want to know how the period of a simple pendulum depends on its length \ell and gravity gg. The period has dimension [T][T]. The only power-law combination of [L]\ell\sim[L] and g[LT2]g\sim[LT^{-2}] that produces [T][T] is /g\sqrt{\ell/g}:

[g]=LLT2=T2=T\left[\sqrt{\frac{\ell}{g}}\right] = \sqrt{\frac{L}{L\,T^{-2}}} = \sqrt{T^2} = T\quad\checkmark

Dimensional analysis predicts T/gT \propto \sqrt{\ell/g}. The exact result is T=2π/gT = 2\pi\sqrt{\ell/g}; the factor of 2π2\pi is dimensionless and cannot be found by this method. But we've derived the dependence on \ell and gg without solving a differential equation.

Limitation: Dimensional analysis cannot determine dimensionless numerical prefactors (like the 2π2\pi above, or the 12\frac{1}{2} in kinematic equations). It also cannot distinguish between adding and subtracting quantities with the same dimension. It is a necessary condition for correctness, not a sufficient one.

1.6 Scientific Notation and Orders of Magnitude

Physical quantities span from the Planck length (1035\sim 10^{-35} m) to the diameter of the observable universe (1026\sim 10^{26} m) — a ratio of 106110^{61}. Standard decimal notation is unworkable at these extremes. Instead every number is expressed in scientific notation:

a×10n,1a<10,nZa \times 10^n, \qquad 1 \leq a < 10, \quad n \in \mathbb{Z}

Examples: the speed of light c=2.998×108 m/sc = 2.998 \times 10^8\text{ m/s}; the electron mass me=9.109×1031 kgm_e = 9.109 \times 10^{-31}\text{ kg}; Avogadro's number NA=6.022×1023 mol1N_A = 6.022 \times 10^{23}\text{ mol}^{-1}.

Orders of Magnitude

The order of magnitude of a number is the power of 10 closest to it. The mass of Earth is 5.97×1024 kg5.97 \times 10^{24}\text{ kg}, so its order of magnitude is 25. Before calculating an answer precisely, every physicist first estimates the answer to the nearest power of 10. A computed answer that differs from the estimate by more than a factor of a few is a warning sign of an error.

Fermi Estimation

Enrico Fermi (1901–1954) was famous for deriving surprisingly accurate answers from rough estimates and order-of-magnitude arithmetic. His method: decompose the unknown quantity into a product of sub-quantities you can estimate, then multiply. Errors tend to partially cancel when you multiply many independent estimates.

Classic example — piano tuners in Chicago: Population 3×106\approx 3 \times 10^6; households 1.5×106\approx 1.5 \times 10^6; 1 in 20 owns a piano 75,000\Rightarrow 75{,}000 pianos; each tuned once per year; a tuner services 4 pianos/day × 250 days/year = 1000 pianos/year. Estimate: 75,000/1000=7575{,}000/1000 = 75 tuners. Real answer: 80\approx 80.

1.7 Significant Figures

The significant figures (sig figs) of a measured number are the digits that carry meaningful information about the measurement's precision. When you write a result, the number of sig figs communicates your confidence in each digit.

Rules for Counting Sig Figs

1. Non-zero digits are always significant: 1234 → 4 sig figs.

2. Zeros between non-zero digits are significant: 1007 → 4 sig figs.

3. Leading zeros (before the first non-zero digit) are never significant: 0.0045 → 2 sig figs (the 4 and 5).

4. Trailing zeros after a decimal point are significant: 3.800 → 4 sig figs. The trailing zeros declare that the measurement was made to that precision.

5. Trailing zeros in an integer without a decimal point are ambiguous: 3000 could be 1, 2, 3, or 4 sig figs. Use scientific notation to eliminate ambiguity: 3×1033 \times 10^3 (1 sig fig) vs 3.000×1033.000 \times 10^3 (4 sig figs).

Sig Figs Through Calculations

Multiplication and division: the result has as many sig figs as the least precise input.

4.56×1.4=6.3846.4(2 sig figs, limited by 1.4)4.56 \times 1.4 = 6.384 \longrightarrow \mathbf{6.4}\quad (2\text{ sig figs, limited by }1.4)

Addition and subtraction: the result has as many decimal places as the input with the fewest decimal places.

12.11+18.0+1.013=31.12331.1(1 decimal place, limited by 18.0)12.11 + 18.0 + 1.013 = 31.123 \longrightarrow \mathbf{31.1}\quad (1\text{ decimal place, limited by }18.0)
Never round intermediate results. Carry full precision through every step of a multi-step calculation and round only the final answer. Rounding intermediate values introduces "rounding error" that accumulates and can shift the final digit of your answer.

1.8 Measurement Uncertainty

No measurement is exact. Every measured value differs from the true value by some amount — the measurement uncertainty. A result reported without its uncertainty is incomplete. We write:

x±δxx \pm \delta x

where xx is the best estimate and δx>0\delta x > 0 is the absolute uncertainty. The relative (fractional) uncertainty is δx/x\delta x / x, often expressed as a percentage.

relative uncertainty=δxx×100%\text{relative uncertainty} = \frac{\delta x}{x} \times 100\%

Random vs Systematic Uncertainty

Random uncertainty arises from unpredictable fluctuations — thermal noise, vibration, the limit of reading an analog scale. Repeated measurements scatter around the true value. Averaging NN independent measurements reduces random uncertainty by N\sqrt{N}:

δxmean=δxN\delta x_{\text{mean}} = \frac{\delta x}{\sqrt{N}}

Systematic uncertainty is a consistent bias that shifts every measurement the same way — a miscalibrated instrument, an uncorrected background, a zero offset. No amount of averaging removes it. Identifying and eliminating systematic errors is the hardest part of experimental physics.

Accuracy vs Precision

Accuracy: how close to the true value. Precision: how reproducible — how tightly clustered repeated measurements are. A precise instrument can be inaccurate (systematic error); an accurate result on average can be imprecise (large scatter). Both must be minimized. In everyday speech these words are used interchangeably, but in science they have distinct meanings.

Propagating Uncertainties

When computing a derived quantity from measured values, the uncertainties propagate. The two fundamental rules:

Sums and differences q=x±yq = x \pm y: absolute uncertainties add:

δq=δx+δy\delta q = \delta x + \delta y

Products and quotients q=xyq = xy or x/yx/y: relative uncertainties add in quadrature:

δqq=(δxx)2+(δyy)2\frac{\delta q}{q} = \sqrt{\left(\frac{\delta x}{x}\right)^2 + \left(\frac{\delta y}{y}\right)^2}

Example: A rectangle has L=12.0±0.2L = 12.0 \pm 0.2 cm and W=5.0±0.1W = 5.0 \pm 0.1 cm. The relative uncertainty in area A=LWA = LW is:

δAA=(0.212.0)2+(0.15.0)2=0.000278+0.0004002.6%\frac{\delta A}{A} = \sqrt{\left(\frac{0.2}{12.0}\right)^2 + \left(\frac{0.1}{5.0}\right)^2} = \sqrt{0.000278 + 0.000400} \approx 2.6\%

Since A=60.0 cm2A = 60.0\text{ cm}^2, the absolute uncertainty is 0.026×60.01.6 cm20.026 \times 60.0 \approx 1.6\text{ cm}^2, giving A=60.0±1.6 cm2A = 60.0 \pm 1.6\text{ cm}^2.

Key Concepts

SI Base Units
Seven fundamental units from which all others are derived: meter (m), kilogram (kg), second (s), ampere (A), kelvin (K), mole (mol), and candela (cd).
Dimensional Analysis
A method of checking equations and converting units by treating dimensions — length LL, mass MM, time TT — as algebraic quantities that must balance on both sides of an equation.
Significant Figures
The meaningful digits in a measured quantity reflecting its precision. For multiplication/division, keep the fewest sig figs of any input. For addition/subtraction, keep the fewest decimal places.
Scientific Notation
Writing numbers as a×10na \times 10^n where 1a<101 \leq a < 10. For example, the speed of light is c=2.998×108 m/sc = 2.998 \times 10^8 \text{ m/s}.
Accuracy vs. Precision
Accuracy measures closeness to the true value. Precision measures reproducibility — how close repeated measurements are to each other. A measurement can be precise without being accurate.
Measurement Uncertainty
Every measurement has inherent uncertainty δx\delta x. We write results as x±δxx \pm \delta x. The relative uncertainty is δx/x\delta x / x, often expressed as a percentage.

Key Equations

Unit Conversion (identity fraction)
1 m100 cm=1\frac{1 \text{ m}}{100 \text{ cm}} = 1
Multiplying any quantity by a unit-conversion fraction equal to 1 changes the unit without changing the physical quantity.
Dimensions of Common Quantities
[v]=LT,[a]=LT2,[F]=MLT2[v] = \frac{L}{T}, \quad [a] = \frac{L}{T^2}, \quad [F] = \frac{ML}{T^2}
Dimensions of velocity, acceleration, and force in terms of base dimensions L, M, T.
Relative Uncertainty
relative uncertainty=δxx×100%\text{relative uncertainty} = \frac{\delta x}{x} \times 100\%
Expresses measurement precision as a percentage of the measured value.
Uncertainty Propagation (product/quotient)
δ(xy)xy=(δxx)2+(δyy)2\frac{\delta(xy)}{xy} = \sqrt{\left(\frac{\delta x}{x}\right)^2 + \left(\frac{\delta y}{y}\right)^2}
For a product or quotient, relative uncertainties add in quadrature.
Worked Example

Unit Conversion: mph to m/s

Problem

Convert a speed of 60 miles per hour to meters per second.

Solution

Write the quantity with its unit.

60mihr60 \, \frac{\text{mi}}{\text{hr}}

Multiply by conversion fractions equal to 1 (1 mi = 1609 m, 1 hr = 3600 s):

60mihr×1609 m1 mi×1 hr3600 s60 \, \frac{\text{mi}}{\text{hr}} \times \frac{1609 \text{ m}}{1 \text{ mi}} \times \frac{1 \text{ hr}}{3600 \text{ s}}

Cancel units and compute:

=60×16093600ms26.8m/s= \frac{60 \times 1609}{3600} \, \frac{\text{m}}{\text{s}} \approx 26.8 \, \text{m/s}
Answer 60 mph ≈ 26.8 m/s
Practice

Exercises

20 problems
Free preview
1
2
2 free · 18 Pro
Exercise 1 / 20 Free
+10 XP
Ruler Reading

Read the position of the marker to the correct number of significant figures (3 sig figs).

1 div = 1 mm = 0.1 cm
Tip estimate one digit between mm marks

Your answer
Position = cm
Exercise 2 / 20 Free
+10 XP
Significant Figures

Which measurement has the <strong>most significant figures</strong>?

Leading zeros never count
Trailing zeros after decimal always count

Select a measurement above

3 of 20

Convert 5.0 km5.0\text{ km} to meters. (1 km = 1000 m)

Unlock Exercise 3

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
4 of 20

A Canadian highway speed limit sign reads 100 km/h. Convert this speed to meters per second.

Unlock Exercise 4

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
5 of 20

A physics experiment runs for 9.00×1039.00 \times 10^3 seconds. Express this duration in hours.

Unlock Exercise 5

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
6 of 20

The diagram shows a measurement of x=8.0x = 8.0 m with error bars. The yellow bars extend ±0.5\pm 0.5 m from the central value. What is the **percentage uncertainty** of this measurement?

Unlock Exercise 6

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
7 of 20

A lab bench measures 2.4 m×0.85 m2.4\text{ m} \times 0.85\text{ m}. Calculate the area and express it with the correct number of significant figures.

Unlock Exercise 7

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
8 of 20

Using dimensional analysis: an equation gives a result with dimensions m2ms\frac{\text{m}^2}{\text{m} \cdot \text{s}}. What physical quantity does this correspond to? Enter the numeric exponent of meters in the simplified result (i.e., the power of m in the final unit m?^?/s).

Unlock Exercise 8

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
9 of 20

The Earth–Sun distance is 1.496×10111.496 \times 10^{11} m (1 AU). Light travels at c=3.00×108c = 3.00 \times 10^8 m/s. How many seconds does sunlight take to reach Earth? Give your answer to 3 significant figures.

Unlock Exercise 9

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
10 of 20

A computer processor has a clock speed of 3.203.20 GHz (gigahertz). Convert this frequency to megahertz (MHz). (1 GHz = 1000 MHz)

Unlock Exercise 10

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
11 of 20

Two lengths are measured: L1=12.3±0.1 cmL_1 = 12.3 \pm 0.1\text{ cm} and L2=8.4±0.2 cmL_2 = 8.4 \pm 0.2\text{ cm}. What is the absolute uncertainty δ(L1+L2)\delta(L_1 + L_2) in centimeters?

Unlock Exercise 11

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
12 of 20

The diagram shows the seven SI base units. Force (the Newton) is a **derived** unit. In terms of base units, 1 N=1 kgmsn1\text{ N} = 1\text{ kg}\cdot\text{m}\cdot\text{s}^n. What is the exponent nn?

Unlock Exercise 12

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
13 of 20

The speed of light is c=2.998×108 m/sc = 2.998 \times 10^8\text{ m/s}. A light-year is the distance light travels in one year. One year 3.156×107 s\approx 3.156 \times 10^7\text{ s}. How many meters is one light-year? Give your answer in the form a×1015a \times 10^{15} and enter the value of aa to 3 sig figs.

Unlock Exercise 13

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
14 of 20

A balance is slightly off-level, with the 250 g standard mass on the right pan. An object on the left pan brings the balance closer to level but not quite. If a second measurement gives the balance reading as m=0.248 kgm = 0.248\text{ kg}, express this mass in grams.

Unlock Exercise 14

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
15 of 20

Three strips of tape have lengths 12.5 cm12.5\text{ cm}, 0.382 cm0.382\text{ cm}, and 4.17 cm4.17\text{ cm}. When you add them, what is the correct sum expressed with the appropriate number of decimal places?

Unlock Exercise 15

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
16 of 20

A student writes the formula v=2Emv = \sqrt{\frac{2E}{m}} where EE is energy (kg·m²/s²) and mm is mass (kg). Check dimensions: what is the dimension of 2E/m\sqrt{2E/m}? Enter 1 if the dimensions equal m/s (velocity), enter 0 if they do not.

Unlock Exercise 16

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
17 of 20

A rectangle has L=12.0±0.2 cmL = 12.0 \pm 0.2\text{ cm} and W=5.0±0.1 cmW = 5.0 \pm 0.1\text{ cm}. Using the rule for products, the relative uncertainty in the area is (δLL)2+(δWW)2\sqrt{\left(\frac{\delta L}{L}\right)^2 + \left(\frac{\delta W}{W}\right)^2}. What is this relative uncertainty as a percentage? Round to 2 sig figs.

Unlock Exercise 17

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
18 of 20

A silicon transistor gate is 10 nm wide. Convert this to meters using scientific notation. What is the width in meters?

Unlock Exercise 18

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
19 of 20

A digital scale displays a mass of 0.07350 kg0.07350\text{ kg}. How many significant figures does this measurement have?

Unlock Exercise 19

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →
20 of 20

Copper has a density of ρ=8.96 g/cm3\rho = 8.96\text{ g/cm}^3. Convert this to SI units of kg/m3\text{kg/m}^3. (1 kg = 1000 g; 1 m = 100 cm)

Unlock Exercise 20

Subscribe to PhysWeb Pro to access all exercises and track your progress.

Upgrade to Pro →

Key Takeaways

  • The seven SI base units underpin all physical measurement.
  • Dimensional analysis checks equations and guides unit conversions — dimensions must match on both sides.
  • Significant figures propagate through calculations: multiply/divide → fewest sig figs; add/subtract → fewest decimal places.
  • State every measurement result as x±δxx \pm \delta x to communicate both value and uncertainty.
  • Always sanity-check numerical answers using dimensional analysis before accepting them.